What is the integral from 0 to 2 of 3y ?

The integral from 0 to 2 of 3y is 6

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integral from 0 to 2 of 3y

\int_{0}^{2} 3 y d y

6

Solution steps

\int_{0}^{2} 3 y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{2} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{2}

= 3 [\frac{y ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= 3 \cdot 2

Simplify

= 6

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