What is the integral from 0 to x/2 of sin(x) ?

The integral from 0 to x/2 of sin(x) is -cos(x/2)+1

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integral from 0 to x/2 of sin(x)

\int_{0}^{\frac{x}{2}} sin (x) d x

- cos (\frac{x}{2}) + 1

Solution steps

\int_{0}^{\frac{x}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{x}{2}}

Compute the boundaries:

- cos (\frac{x}{2}) + 1

= - cos (\frac{x}{2}) + 1

\int_{0}^{x^{3}} 1 d x

\int_{- 6}^{- 2} (x - 3) d x

\int_{0}^{300} \frac{11}{3} x d x

\int_{- \frac{π}{2}}^{0} cos (x) d x

\int_{0}^{2} 2 x^{2} x^{3} + 1 d x

What is the integral from 0 to x/2 of sin(x) ?
The integral from 0 to x/2 of sin(x) is -cos(x/2)+1