What is the integral from 4 to 0 of x^2 ?

The integral from 4 to 0 of x^2 is -64/3

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integral from 4 to 0 of x^2

\int_{4}^{0} x^{2} d x

- \frac{64}{3}

Decimal

- 21.33333 \dots

Solution steps

\int_{4}^{0} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= - [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= - \frac{64}{3}

\int_{0}^{12} \frac{x}{16 + 4 x} d x

\int_{1}^{2} 3 x - x^{2} - 2 d x

\int_{6.1}^{7.2} 12 x^{2} - 6 x + 4 d x

\int_{0}^{1} 9 x^{2} + 144 d x

\int_{0}^{1} x \cdot 4 x^{3} d x

What is the integral from 4 to 0 of x^2 ?
The integral from 4 to 0 of x^2 is -64/3