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Popular >

integral from 0 to 2 of (x-|x-1|)

Solution

\int_{0}^{2} (x - ∣ x - 1 ∣) d x

Solution

1

Solution steps

\int_{0}^{2} x - ∣ x - 1 ∣ d x

Eliminate Absolutes

= \int_{0}^{1} x - (- x + 1) d x + \int_{1}^{2} x - (x - 1) d x

\int_{0}^{1} x - (- x + 1) d x = 0

\int_{1}^{2} x - (x - 1) d x = 1

= 0 + 1

Simplify

= 1

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (x-|x-1|) ?
The integral from 0 to 2 of (x-|x-1|) is 1