What is (\partial)/(\partial x)(x^2-2y) ?

The answer to (\partial)/(\partial x)(x^2-2y) is 2x

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(\partial)/(\partial x)(x^2-2y)

\frac{\partial}{\partial x} (x^{2} - 2 y)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 y) = 0

= 2 x - 0

Simplify

= 2 x

\frac{4}{x}, 16 x, \frac{1}{16} x

\int x^{2} x + 4 d x

\int \frac{sin ( 2 x )}{1 + cos ^{2} ( x )} d x

\int \frac{x ^{2} + 1}{( x + 1 ) ^{2}} e^{x} d x

x \to 1 + lim (x^{2} - 4 x + 3)

What is (\partial)/(\partial x)(x^2-2y) ?
The answer to (\partial)/(\partial x)(x^2-2y) is 2x