What is the integral from 0 to pi of sin(x ?

The integral from 0 to pi of sin(x is sin(d)(pi^2)/2

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integral from 0 to pi of sin(x

\int_{0}^{π} sin (d) x d x

sin (d) \frac{π ^{2}}{2}

Solution steps

\int_{0}^{π} sin (d) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (d) \cdot \int_{0}^{π} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{π}

= sin (d) [\frac{x ^{2}}{2}]_{0}^{π}

Compute the boundaries:

\frac{π ^{2}}{2}

= sin (d) \frac{π ^{2}}{2}

\int_{- 2}^{3} - 3 ∣ x ∣ d x

\int_{0}^{3} 3 x^{2} + 1 d x

\int_{0}^{1} e^{x} - e x d x

\int_{3}^{5} \frac{y - 3}{y - 2} d y

\int_{0}^{π} 2 x \cdot sin (x) d x

What is the integral from 0 to pi of sin(x ?
The integral from 0 to pi of sin(x is sin(d)(pi^2)/2