What is the integral from 0 to 10 of 1/((1+x)^2) ?

The integral from 0 to 10 of 1/((1+x)^2) is 10/11

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integral from 0 to 10 of 1/((1+x)^2)

\int_{0}^{10} \frac{1}{( 1 + x ) ^{2}} d x

\frac{10}{11}

Decimal

0.90909 \dots

Solution steps

\int_{0}^{10} \frac{1}{( 1 + x ) ^{2}} d x

Apply u-substitution

: \int_{1}^{11} \frac{1}{u ^{2}} d u

= \int_{1}^{11} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{1}^{11}

= [- \frac{1}{u}]_{1}^{11}

Compute the boundaries:

\frac{10}{11}

= \frac{10}{11}

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What is the integral from 0 to 10 of 1/((1+x)^2) ?
The integral from 0 to 10 of 1/((1+x)^2) is 10/11