What is the integral from-infinity to-1 of x^{-13/5} ?

The integral from-infinity to-1 of x^{-13/5} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to-1 of x^{-13/5}

\int_{- \infty}^{- 1} x^{- \frac{13}{5}} d x

diverges

Solution steps

\int_{- \infty}^{- 1} x^{- \frac{13}{5}} d x

Compute the indefinite integral:

\int x^{- \frac{13}{5}} d x = - \frac{5}{8 x ^{\frac{8}{5}}} + C

Compute the boundaries:

\int_{- \infty}^{- 1} x^{- \frac{13}{5}} d x =

diverges

= diverges

\int_{0}^{π} (sin (2 x)) d x

\int_{0}^{1} (3 y)^{2} d y

\int_{- 1}^{3} 6 x y - 5 e^{y} d x

\int_{0}^{4} \frac{x}{4 + x ^{2}} d x

\int_{- 2}^{0} x^{3} + 3 x^{2} + 2 x d x

What is the integral from-infinity to-1 of x^{-13/5} ?
The integral from-infinity to-1 of x^{-13/5} is diverges