What is the integral from 1 to infinity of e^{-x+1} ?

The integral from 1 to infinity of e^{-x+1} is 1

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integral from 1 to infinity of e^{-x+1}

\int_{1}^{\infty} e^{- x + 1} d x

1

Solution steps

\int_{1}^{\infty} e^{- x + 1} d x

Compute the indefinite integral:

\int e^{- x + 1} d x = - e^{- x + 1} + C

Compute the boundaries:

\int_{1}^{\infty} e^{- x + 1} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

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What is the integral from 1 to infinity of e^{-x+1} ?
The integral from 1 to infinity of e^{-x+1} is 1