What is the integral from 0 to infinity of 1-e^{-2x} ?

The integral from 0 to infinity of 1-e^{-2x} is diverges

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integral from 0 to infinity of 1-e^{-2x}

\int_{0}^{\infty} 1 - e^{- 2 x} d x

diverges

Solution steps

\int_{0}^{\infty} 1 - e^{- 2 x} d x

Compute the indefinite integral:

\int 1 - e^{- 2 x} d x = x + \frac{1}{2} e^{- 2 x} + C

Compute the boundaries:

\int_{0}^{\infty} 1 - e^{- 2 x} d x =

diverges

= diverges

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What is the integral from 0 to infinity of 1-e^{-2x} ?
The integral from 0 to infinity of 1-e^{-2x} is diverges