What is the integral from-2 to-1 of |x| ?

The integral from-2 to-1 of |x| is 3/2

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integral from-2 to-1 of |x|

\int_{- 2}^{- 1} ∣ x ∣ d x

\frac{3}{2}

Decimal

1.5

Solution steps

\int_{- 2}^{- 1} ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 2}^{- 1} - x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 2}^{- 1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 2}^{- 1}

= - [\frac{x ^{2}}{2}]_{- 2}^{- 1}

Compute the boundaries:

- \frac{3}{2}

= - (- \frac{3}{2})

Simplify

= \frac{3}{2}

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What is the integral from-2 to-1 of |x| ?
The integral from-2 to-1 of |x| is 3/2