What is the integral from pi to (3pi)/2 of-sin(x) ?

The integral from pi to (3pi)/2 of-sin(x) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from pi to (3pi)/2 of-sin(x)

\int_{π}^{\frac{3 π}{2}} - sin (x) d x

1

Solution steps

\int_{π}^{\frac{3 π}{2}} - sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{π}^{\frac{3 π}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{π}^{\frac{3 π}{2}}

Compute the boundaries:

- 1

= - (- 1)

Simplify

= 1

\int_{- 1}^{2} 8 x - x^{2} - 7 d x

\int_{- 1}^{0} - 2 x + 3 d x

\int_{0}^{2} \frac{2}{x + 1} d x

\int_{2}^{6} x^{2} + 7 d x

\int_{- π}^{0} (π + x) sin (n x) d x

What is the integral from pi to (3pi)/2 of-sin(x) ?
The integral from pi to (3pi)/2 of-sin(x) is 1