What is the integral from 0 to 3 of (x^2)^2 ?

The integral from 0 to 3 of (x^2)^2 is 243/5

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integral from 0 to 3 of (x^2)^2

\int_{0}^{3} (x^{2})^{2} d x

\frac{243}{5}

Decimal

48.6

Solution steps

\int_{0}^{3} (x^{2})^{2} d x

Simplify

(x^{2})^{2} : x^{4}

= \int_{0}^{3} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{0}^{3}

= [\frac{x ^{5}}{5}]_{0}^{3}

Compute the boundaries:

\frac{243}{5}

= \frac{243}{5}

\int_{- 2}^{3} (3 x^{4} - 5 x^{3} - x - 6) d x

\int_{0}^{1} x \cdot 1 + x^{2} d x

\int_{1}^{2} (- x^{2} + 5) d x

\int_{0}^{1} \frac{2 x ^{3}}{x ^{2} + x} d x

\int_{x}^{1} e^{- y^{2}} d y

What is the integral from 0 to 3 of (x^2)^2 ?
The integral from 0 to 3 of (x^2)^2 is 243/5