What is the integral from-3/2 to 1 of (x^3-4x) ?

The integral from-3/2 to 1 of (x^3-4x) is 95/64

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integral from-3/2 to 1 of (x^3-4x)

\int_{- \frac{3}{2}}^{1} (x^{3} - 4 x) d x

\frac{95}{64}

Decimal

1.484375

Solution steps

\int_{- \frac{3}{2}}^{1} x^{3} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- \frac{3}{2}}^{1} x^{3} d x - \int_{- \frac{3}{2}}^{1} 4 x d x

\int_{- \frac{3}{2}}^{1} x^{3} d x = - \frac{65}{64}

\int_{- \frac{3}{2}}^{1} 4 x d x = - \frac{5}{2}

= - \frac{65}{64} - (- \frac{5}{2})

Simplify

- \frac{65}{64} - (- \frac{5}{2}) : \frac{95}{64}

= \frac{95}{64}

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What is the integral from-3/2 to 1 of (x^3-4x) ?
The integral from-3/2 to 1 of (x^3-4x) is 95/64