What is the integral from-pi to 0 of-cos(x) ?

The integral from-pi to 0 of-cos(x) is 0

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integral from-pi to 0 of-cos(x)

\int_{- π}^{0} - cos (x) d x

0

Solution steps

\int_{- π}^{0} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- π}^{0} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{- π}^{0}

Compute the boundaries:

0

= - 0

Simplify

= 0

\int_{0}^{\frac{1}{2}} (2 x + 1)^{- 2} d x

\int_{0}^{1} (2 x - 1)^{4} d x

\int_{0}^{1} 100 e^{- 0.01 x} d x

\int_{1}^{e} 6 t^{2} ln (t) d t

\int_{1}^{2} t \frac{1}{2} t^{2} + 9 d t

What is the integral from-pi to 0 of-cos(x) ?
The integral from-pi to 0 of-cos(x) is 0