What is the integral from 0 to infinity of e^{-1x} ?

The integral from 0 to infinity of e^{-1x} is 1

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integral from 0 to infinity of e^{-1x}

\int_{0}^{\infty} e^{- 1 x} d x

1

Solution steps

\int_{0}^{\infty} e^{- 1 \cdot x} d x

Compute the indefinite integral:

\int e^{- 1 \cdot x} d x = - e^{- x} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- 1 \cdot x} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

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What is the integral from 0 to infinity of e^{-1x} ?
The integral from 0 to infinity of e^{-1x} is 1