What is the integral from 0 to 2 of 7^x ?

The integral from 0 to 2 of 7^x is (48)/(ln(7))

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integral from 0 to 2 of 7^x

\int_{0}^{2} 7^{x} d x

\frac{48}{ln ( 7 )}

Decimal

24.66712 \dots

Solution steps

\int_{0}^{2} 7^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{7 ^{x}}{ln ( 7 )}]_{0}^{2}

Compute the boundaries:

\frac{48}{ln ( 7 )}

= \frac{48}{ln ( 7 )}

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What is the integral from 0 to 2 of 7^x ?
The integral from 0 to 2 of 7^x is (48)/(ln(7))