What is the integral from 1 to 4 of (9sqrt(x)-6x) ?

The integral from 1 to 4 of (9sqrt(x)-6x) is -3

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integral from 1 to 4 of (9sqrt(x)-6x)

\int_{1}^{4} (9 x - 6 x) d x

- 3

Solution steps

\int_{1}^{4} 9 x - 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 9 x d x - \int_{1}^{4} 6 x d x

\int_{1}^{4} 9 x d x = 42

\int_{1}^{4} 6 x d x = 45

= 42 - 45

Simplify

= - 3

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What is the integral from 1 to 4 of (9sqrt(x)-6x) ?
The integral from 1 to 4 of (9sqrt(x)-6x) is -3