What is the integral from 0 to 1 of 4x(1-y) ?

The integral from 0 to 1 of 4x(1-y) is 2(1-y)

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integral from 0 to 1 of 4x(1-y)

\int_{0}^{1} 4 x (1 - y) d x

2 (1 - y)

Solution steps

\int_{0}^{1} 4 x (1 - y) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (1 - y) \cdot 4 \cdot \int_{0}^{1} x d x

\int_{0}^{1} x d x = \frac{1}{2}

= (1 - y) \cdot 4 \cdot \frac{1}{2}

Simplify

(1 - y) \cdot 4 \cdot \frac{1}{2} : 2 (1 - y)

= 2 (1 - y)

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What is the integral from 0 to 1 of 4x(1-y) ?
The integral from 0 to 1 of 4x(1-y) is 2(1-y)