What is the integral from-5 to 5 of 4/(x^3) ?

The integral from-5 to 5 of 4/(x^3) is diverges

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integral from-5 to 5 of 4/(x^3)

\int_{- 5}^{5} \frac{4}{x ^{3}} d x

diverges

Solution steps

\int_{- 5}^{5} \frac{4}{x ^{3}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 5}^{0} \frac{4}{x ^{3}} d x + \int_{0}^{5} \frac{4}{x ^{3}} d x

\int_{- 5}^{0} \frac{4}{x ^{3}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{1}^{3} x^{3} e^{x} d x

\int_{0}^{1} 3 t^{3} d t

\int_{- 3}^{2} 3 x^{2} d x

\int_{- 1}^{2} (3 x - 1 x^{1}) d x

\int_{0}^{\frac{π}{2}} \frac{1 - cos ( 2 t )}{2} d t

What is the integral from-5 to 5 of 4/(x^3) ?
The integral from-5 to 5 of 4/(x^3) is diverges