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Popular >

integral from 1 to 3 of (3x-9)

Solution

\int_{1}^{3} (3 x - 9) d x

Solution

- 6

Solution steps

\int_{1}^{3} 3 x - 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 3 x d x - \int_{1}^{3} 9 d x

\int_{1}^{3} 3 x d x = 12

\int_{1}^{3} 9 d x = 18

= 12 - 18

Simplify

= - 6

Graph

Popular Examples

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\int_{0}^{π} cos^{4} (5 x) d x

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\int_{4}^{9} \frac{3}{x - 2} d x

integral from 0 to 2 of (x^3-5x^2+6x)

\int_{0}^{2} (x^{3} - 5 x^{2} + 6 x) d x

integral from-pi to pi of 1+x

\int_{- π}^{π} 1 + x d x

integral from 4 to 0 of 4x-x^2

\int_{4}^{0} 4 x - x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 3 of (3x-9) ?
The integral from 1 to 3 of (3x-9) is -6