What is the integral from-1 to 1 of xsqrt(x^2+4) ?

The integral from-1 to 1 of xsqrt(x^2+4) is 0

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integral from-1 to 1 of xsqrt(x^2+4)

\int_{- 1}^{1} x x^{2} + 4 d x

0

Solution steps

\int_{- 1}^{1} x x^{2} + 4 d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x x^{2} + 4 :

Odd

= 0

\int_{- 1}^{2} x (1 - x^{2}) d x

\int_{0}^{\frac{π}{3}} sin (3 y) cos (y) d y

\int_{0}^{0} 16 - t^{2} d t

\int_{- 1}^{3} (- x + 2) d x

\int_{1}^{5} 3 + 4 x^{- 4} d x

What is the integral from-1 to 1 of xsqrt(x^2+4) ?
The integral from-1 to 1 of xsqrt(x^2+4) is 0