en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of-x^2+4x

Solution

\int_{0}^{2} - x^{2} + 4 x d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{0}^{2} - x^{2} + 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} x^{2} d x + \int_{0}^{2} 4 x d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 4 x d x = 8

= - \frac{8}{3} + 8

Simplify

- \frac{8}{3} + 8 : \frac{16}{3}

= \frac{16}{3}

Graph

Popular Examples

integral from 1 to 2 of r^7sin(2r^4)

\int_{1}^{2} r^{7} sin (2 r^{4}) d r

integral from 0 to 12 of x^3

\int_{0}^{12} x^{3} d x

integral from 1 to 5 of |t^2-2t-8|

\int_{1}^{5} t^{2} - 2 t - 8 d t

integral from 0 to 1 of ((x^2))/(x^2+1)

\int_{0}^{1} \frac{( x ^{2} )}{x ^{2} + 1} d x

integral from x to 1 of 1/t

\int_{x}^{1} \frac{1}{t} d t

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of-x^2+4x ?
The integral from 0 to 2 of-x^2+4x is 16/3