What is the integral from 0 to sqrt(y^2-9x^2 of)z ?

The integral from 0 to sqrt(y^2-9x^2 of)z is (y^2-9x^2)/2

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integral from 0 to sqrt(y^2-9x^2 of)z

\int_{0}^{y^{2} - 9 x^{2}} z d z

\frac{y ^{2} - 9 x ^{2}}{2}

Solution steps

\int_{0}^{y^{2} - 9 x^{2}} z d z

Apply the Power Rule

: [\frac{z ^{2}}{2}]_{0}^{y^{2} - 9 x^{2}}

= [\frac{z ^{2}}{2}]_{0}^{y^{2} - 9 x^{2}}

Compute the boundaries:

\frac{y ^{2} - 9 x ^{2}}{2}

= \frac{y ^{2} - 9 x ^{2}}{2}

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What is the integral from 0 to sqrt(y^2-9x^2 of)z ?
The integral from 0 to sqrt(y^2-9x^2 of)z is (y^2-9x^2)/2