What is the integral from 1 to 6 of (-x^2+7x-6) ?

The integral from 1 to 6 of (-x^2+7x-6) is 125/6

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integral from 1 to 6 of (-x^2+7x-6)

\int_{1}^{6} (- x^{2} + 7 x - 6) d x

\frac{125}{6}

Decimal

20.83333 \dots

Solution steps

\int_{1}^{6} - x^{2} + 7 x - 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{1}^{6} x^{2} d x + \int_{1}^{6} 7 x d x - \int_{1}^{6} 6 d x

\int_{1}^{6} x^{2} d x = \frac{215}{3}

\int_{1}^{6} 7 x d x = \frac{245}{2}

\int_{1}^{6} 6 d x = 30

= - \frac{215}{3} + \frac{245}{2} - 30

Simplify

- \frac{215}{3} + \frac{245}{2} - 30 : \frac{125}{6}

= \frac{125}{6}

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What is the integral from 1 to 6 of (-x^2+7x-6) ?
The integral from 1 to 6 of (-x^2+7x-6) is 125/6