What is the integral from-1 to 2 of e^{x^2} ?

The integral from-1 to 2 of e^{x^2} is (sqrt(pi)\erfi(2)-sqrt(pi)\erfi(-1))/2

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integral from-1 to 2 of e^{x^2}

\int_{- 1}^{2} e^{x^{2}} d x

\frac{π erfi ( 2 ) - π erfi ( - 1 )}{2}

Solution steps

\int_{- 1}^{2} e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= [\frac{π}{2} erfi (x)]_{- 1}^{2}

Compute the boundaries:

\frac{π erfi ( 2 ) - π erfi ( - 1 )}{2}

= \frac{π erfi ( 2 ) - π erfi ( - 1 )}{2}

\int_{0}^{a} 2 x d x

\int_{2}^{7} e^{2 - x} d x

\int_{- 3}^{3} x x^{4} + 1 d x

\int_{0}^{2 π} (1 + sin (θ))^{2} d θ

\int_{1}^{- 1} x d x

What is the integral from-1 to 2 of e^{x^2} ?
The integral from-1 to 2 of e^{x^2} is (sqrt(pi)\erfi(2)-sqrt(pi)\erfi(-1))/2