What is the integral from-4 to 12 of sqrt(x+4) ?

The integral from-4 to 12 of sqrt(x+4) is 128/3

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integral from-4 to 12 of sqrt(x+4)

\int_{- 4}^{12} x + 4 d x

\frac{128}{3}

Decimal

42.66666 \dots

Solution steps

\int_{- 4}^{12} x + 4 d x

Apply u-substitution

: \int_{0}^{16} u d u

= \int_{0}^{16} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{16}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{16}

Compute the boundaries:

\frac{128}{3}

= \frac{128}{3}

\int_{- 1}^{0} x^{\frac{1}{5}} - x d x

\int_{- 4}^{1} 1 d x

\int_{0}^{\infty} x e^{- y} d y

\int_{3}^{4} (2 x + 9) d x

\int_{0}^{x} e^{t^{2}} d t

What is the integral from-4 to 12 of sqrt(x+4) ?
The integral from-4 to 12 of sqrt(x+4) is 128/3