What is the integral from 2 to 3 of (3x^2-(x^4)/4) ?

The integral from 2 to 3 of (3x^2-(x^4)/4) is 169/20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 3 of (3x^2-(x^4)/4)

\int_{2}^{3} (3 x^{2} - \frac{x ^{4}}{4}) d x

\frac{169}{20}

Decimal

8.45

Solution steps

\int_{2}^{3} 3 x^{2} - \frac{x ^{4}}{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} 3 x^{2} d x - \int_{2}^{3} \frac{x ^{4}}{4} d x

\int_{2}^{3} 3 x^{2} d x = 19

\int_{2}^{3} \frac{x ^{4}}{4} d x = \frac{211}{20}

= 19 - \frac{211}{20}

Simplify

19 - \frac{211}{20} : \frac{169}{20}

= \frac{169}{20}

\int_{0}^{1} x sin (1 - x^{2}) d x

\int_{1}^{3} (4 x - 3) d x

\int_{\frac{π}{3}}^{\frac{3 π}{4}} sin (x) d x

\int_{0}^{2} 4 e^{- s t} d t

\int_{- 3}^{1} x (x - 1) (x + 3) d x

What is the integral from 2 to 3 of (3x^2-(x^4)/4) ?
The integral from 2 to 3 of (3x^2-(x^4)/4) is 169/20