What is the integral from 5 to-5 of (3x+2)^2 ?

The integral from 5 to-5 of (3x+2)^2 is -790

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integral from 5 to-5 of (3x+2)^2

\int_{5}^{- 5} (3 x + 2)^{2} d x

- 790

Solution steps

\int_{5}^{- 5} (3 x + 2)^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 5}^{5} (3 x + 2)^{2} d x

Expand

(3 x + 2)^{2} : 9 x^{2} + 12 x + 4

= - \int_{- 5}^{5} 9 x^{2} + 12 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int_{- 5}^{5} 9 x^{2} d x + \int_{- 5}^{5} 12 x d x + \int_{- 5}^{5} 4 d x)

\int_{- 5}^{5} 9 x^{2} d x = 750

\int_{- 5}^{5} 12 x d x = 0

\int_{- 5}^{5} 4 d x = 40

= - (750 + 0 + 40)

Simplify

= - 790

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What is the integral from 5 to-5 of (3x+2)^2 ?
The integral from 5 to-5 of (3x+2)^2 is -790