What is the integral from 0.6 to 1 of 3x^2 ?

The integral from 0.6 to 1 of 3x^2 is 0.78399…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0.6 to 1 of 3x^2

\int_{0.6}^{1} 3 x^{2} d x

0.78399 \dots

Solution steps

\int_{0.6}^{1} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0.6}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0.6}^{1}

= 3 [\frac{x ^{3}}{3}]_{0.6}^{1}

Simplify

= 3 [0.33333 \dots x^{3}]_{0.6}^{1}

Compute the boundaries:

0.26133 \dots

= 3 \cdot 0.26133 \dots

Simplify

= 0.78399 \dots

\int_{0}^{2} π (4 - x^{2}) d x

\int_{1}^{3} \frac{π}{y} d y

\int_{0}^{l n (4)} e^{3 x} d x

\int_{1}^{4} x e^{6 x^{2} - 9} d x

\int_{\frac{1}{e}}^{e^{2}} \frac{x ^{3} + 1}{x} d x

What is the integral from 0.6 to 1 of 3x^2 ?
The integral from 0.6 to 1 of 3x^2 is 0.78399…