What is the integral from 1 to infinity of 1/(7^x) ?

The integral from 1 to infinity of 1/(7^x) is 1/(7ln(7))

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integral from 1 to infinity of 1/(7^x)

\int_{1}^{\infty} \frac{1}{7 ^{x}} d x

\frac{1}{7 ln ( 7 )}

Decimal

0.07341 \dots

Solution steps

\int_{1}^{\infty} \frac{1}{7 ^{x}} d x

Compute the indefinite integral:

\int \frac{1}{7 ^{x}} d x = - \frac{1}{ln ( 7 ) \cdot 7 ^{x}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{7 ^{x}} d x = 0 - (- \frac{1}{7 ln ( 7 )})

= 0 - (- \frac{1}{7 ln ( 7 )})

Simplify

= \frac{1}{7 ln ( 7 )}

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What is the integral from 1 to infinity of 1/(7^x) ?
The integral from 1 to infinity of 1/(7^x) is 1/(7ln(7))