What is the integral from 0 to 2 of (x^4) ?

The integral from 0 to 2 of (x^4) is 32/5

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integral from 0 to 2 of (x^4)

\int_{0}^{2} (x^{4}) d x

\frac{32}{5}

Decimal

6.4

Solution steps

\int_{0}^{2} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{0}^{2}

= [\frac{x ^{5}}{5}]_{0}^{2}

Compute the boundaries:

\frac{32}{5}

= \frac{32}{5}

\int_{0}^{4} \frac{1}{( x - 2 ) ^{3}} d x

\int_{0}^{5} z e^{- z} d z

\int_{1}^{2} ln (2 x) - ln (x) d x

\int_{0}^{5} h (x) d x

\int_{- 1}^{2} (5 x - 5) d x

What is the integral from 0 to 2 of (x^4) ?
The integral from 0 to 2 of (x^4) is 32/5