What is the integral from-1 to 0 of (e^x) ?

The integral from-1 to 0 of (e^x) is 1-1/e

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 0 of (e^x)

\int_{- 1}^{0} (e^{x}) d x

1 - \frac{1}{e}

Decimal

0.63212 \dots

Solution steps

\int_{- 1}^{0} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{- 1}^{0}

Compute the boundaries:

1 - \frac{1}{e}

= 1 - \frac{1}{e}

\int_{0}^{\infty} e^{- s} d s

\int_{5}^{8} \frac{1}{x - 2} d x

\int_{1}^{3} t d t

\int_{- 2}^{1} 8 x cos (2 x^{2}) d x

\int_{0}^{1} (x + 3 1 - x^{2}) d x

What is the integral from-1 to 0 of (e^x) ?
The integral from-1 to 0 of (e^x) is 1-1/e