What is the integral from y to x of 1/x ?

The integral from y to x of 1/x is ln|x|-ln|y|

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integral from y to x of 1/x

\int_{y}^{x} \frac{1}{x} d x

ln ∣ x ∣ - ln ∣ y ∣

Solution steps

\int_{y}^{x} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{y}^{x}

Compute the boundaries:

ln ∣ x ∣ - ln ∣ y ∣

= ln ∣ x ∣ - ln ∣ y ∣

\int_{- 2}^{4} x^{2} ∣ x - 1 ∣ d x

\int_{1}^{9} 5 u d u

\int_{- 5}^{4} \frac{1}{2} x d x

\int_{5}^{10} \frac{1}{x} d x

\int_{0}^{l n (2)} 1

What is the integral from y to x of 1/x ?
The integral from y to x of 1/x is ln|x|-ln|y|