What is the integral from 0 to 4 of x^2-2y^2 ?

The integral from 0 to 4 of x^2-2y^2 is 64/3-8y^2

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integral from 0 to 4 of x^2-2y^2

\int_{0}^{4} x^{2} - 2 y^{2} d x

\frac{64}{3} - 8 y^{2}

Solution steps

\int_{0}^{4} x^{2} - 2 y^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 2 y^{2} d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 2 y^{2} d x = 8 y^{2}

= \frac{64}{3} - 8 y^{2}

\int_{0}^{4} \frac{2 x}{x ^{2} + 1} d x

\int_{0}^{1} x + y + 1 d x

\int_{1}^{7} \frac{3 ( ln ( x ) ) ^{2}}{x} d x

\int_{3}^{5} 6 t - 18 d t

\int_{- 1}^{1} (x^{2} + y^{2}) d y

What is the integral from 0 to 4 of x^2-2y^2 ?
The integral from 0 to 4 of x^2-2y^2 is 64/3-8y^2