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Popular >

integral from 0 to 4 of (6t-3)

Solution

\int_{0}^{4} (6 t - 3) d t

Solution

36

Solution steps

\int_{0}^{4} 6 t - 3 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 6 t d t - \int_{0}^{4} 3 d t

\int_{0}^{4} 6 t d t = 48

\int_{0}^{4} 3 d t = 12

= 48 - 12

Simplify

= 36

Graph

Popular Examples

integral from 2 to 3 of 4

\int_{2}^{3} 4 d x

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\int_{- 1}^{1} 6 x d x

integral from 0 to 9 of sqrt(5t)

\int_{0}^{9} 5 t d t

integral from 0 to 1000 of 0.03q+0.1

\int_{0}^{1000} 0.03 q + 0.1 d q

integral from 0 to 3 of 4tsqrt(t^2+1)

\int_{0}^{3} 4 t t^{2} + 1 d t

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (6t-3) ?
The integral from 0 to 4 of (6t-3) is 36