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Popular >

integral from 0 to 2 of-x^2+x

Solution

\int_{0}^{2} - x^{2} + x d x

Solution

- \frac{2}{3}

+1

Decimal

- 0.66666 \dots

Solution steps

\int_{0}^{2} - x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} x^{2} d x + \int_{0}^{2} x d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} x d x = 2

= - \frac{8}{3} + 2

Simplify

- \frac{8}{3} + 2 : - \frac{2}{3}

= - \frac{2}{3}

Graph

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\int_{2}^{6} \frac{4}{x} - \frac{8}{x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of-x^2+x ?
The integral from 0 to 2 of-x^2+x is -2/3