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Popular >

integral from-1 to 1 of x^4-x^2

Solution

\int_{- 1}^{1} x^{4} - x^{2} d x

Solution

- \frac{4}{15}

+1

Decimal

- 0.26666 \dots

Solution steps

\int_{- 1}^{1} x^{4} - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{4} d x - \int_{- 1}^{1} x^{2} d x

\int_{- 1}^{1} x^{4} d x = \frac{2}{5}

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

= \frac{2}{5} - \frac{2}{3}

Simplify

\frac{2}{5} - \frac{2}{3} : - \frac{4}{15}

= - \frac{4}{15}

Graph

Popular Examples

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\int_{- \frac{3}{2}}^{\frac{1}{2}} (x^{3} - 4 x) d x

integral from-2 to 3 of (x+6)-x^2

\int_{- 2}^{3} (x + 6) - x^{2} d x

integral from-infinity to-4 of θe^θ

\int_{- \infty}^{- 4} θ e^{θ} d θ

integral from 0 to 1 of (4x-3x^2)

\int_{0}^{1} (4 x - 3 x^{2}) d x

integral from 2 to 6 of (2x+1)ln(x+1)

\int_{2}^{6} (2 x + 1) ln (x + 1) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of x^4-x^2 ?
The integral from-1 to 1 of x^4-x^2 is -4/15