What is the integral from 1 to 3 of 7x^2 ?

The integral from 1 to 3 of 7x^2 is 182/3

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integral from 1 to 3 of 7x^2

\int_{1}^{3} 7 x^{2} d x

\frac{182}{3}

Decimal

60.66666 \dots

Solution steps

\int_{1}^{3} 7 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{3}

= 7 [\frac{x ^{3}}{3}]_{1}^{3}

Compute the boundaries:

\frac{26}{3}

= 7 \cdot \frac{26}{3}

Simplify

= \frac{182}{3}

\int_{- 3}^{3} x^{2} - 4 d x

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\int_{0}^{0.5} \frac{1}{1 + x ^{4}} d x

\int_{0}^{3} e^{- y^{2}} d y

\int_{0}^{3} x (x - 3) (x - 1) d x

What is the integral from 1 to 3 of 7x^2 ?
The integral from 1 to 3 of 7x^2 is 182/3