What is the integral from-1 to 2 of (y^2-y-2) ?

The integral from-1 to 2 of (y^2-y-2) is -9/2

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integral from-1 to 2 of (y^2-y-2)

\int_{- 1}^{2} (y^{2} - y - 2) d y

- \frac{9}{2}

Decimal

- 4.5

Solution steps

\int_{- 1}^{2} y^{2} - y - 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} y^{2} d y - \int_{- 1}^{2} y d y - \int_{- 1}^{2} 2 d y

\int_{- 1}^{2} y^{2} d y = 3

\int_{- 1}^{2} y d y = \frac{3}{2}

\int_{- 1}^{2} 2 d y = 6

= 3 - \frac{3}{2} - 6

Simplify

3 - \frac{3}{2} - 6 : - \frac{9}{2}

= - \frac{9}{2}

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What is the integral from-1 to 2 of (y^2-y-2) ?
The integral from-1 to 2 of (y^2-y-2) is -9/2