What is the integral from 1 to 2 of (x-1)^3 ?

The integral from 1 to 2 of (x-1)^3 is 1/4

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integral from 1 to 2 of (x-1)^3

\int_{1}^{2} (x - 1)^{3} d x

\frac{1}{4}

Decimal

0.25

Solution steps

\int_{1}^{2} (x - 1)^{3} d x

Apply u-substitution

: \int_{0}^{1} u^{3} d u

= \int_{0}^{1} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{0}^{1}

= [\frac{u ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= \frac{1}{4}

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What is the integral from 1 to 2 of (x-1)^3 ?
The integral from 1 to 2 of (x-1)^3 is 1/4