What is the integral from-1 to 3 of 1/((y+2)^2) ?

The integral from-1 to 3 of 1/((y+2)^2) is 4/5

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integral from-1 to 3 of 1/((y+2)^2)

\int_{- 1}^{3} \frac{1}{( y + 2 ) ^{2}} d y

\frac{4}{5}

Decimal

0.8

Solution steps

\int_{- 1}^{3} \frac{1}{( y + 2 ) ^{2}} d y

Apply u-substitution

: \int_{1}^{5} \frac{1}{u ^{2}} d u

= \int_{1}^{5} \frac{1}{u ^{2}} d u

Apply the Power Rule

: [- \frac{1}{u}]_{1}^{5}

= [- \frac{1}{u}]_{1}^{5}

Compute the boundaries:

\frac{4}{5}

= \frac{4}{5}

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What is the integral from-1 to 3 of 1/((y+2)^2) ?
The integral from-1 to 3 of 1/((y+2)^2) is 4/5