What is the integral from 0 to 3 of 6x^2 ?

The integral from 0 to 3 of 6x^2 is 54

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of 6x^2

\int_{0}^{3} 6 x^{2} d x

54

Solution steps

\int_{0}^{3} 6 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{3}

= 6 [\frac{x ^{3}}{3}]_{0}^{3}

Compute the boundaries:

9

= 6 \cdot 9

Simplify

= 54

\int_{- \frac{π}{3}}^{\frac{π}{3}} 2 sin (x) d x

\int_{- 1}^{2} (x + 2)^{2} - (x^{2})^{2} d x

\int_{0}^{1} π (x e^{x})^{2} d x

\int_{1.2}^{5.4} 1.6 x e^{\frac{x}{3}} d x

\int_{0}^{1} sin^{4} (x) \cdot cos (x) d x

What is the integral from 0 to 3 of 6x^2 ?
The integral from 0 to 3 of 6x^2 is 54