What is the integral from 1 to 3 of 95+300t^2-10t ?

The integral from 1 to 3 of 95+300t^2-10t is 2750

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integral from 1 to 3 of 95+300t^2-10t

\int_{1}^{3} 95 + 300 t^{2} - 10 t d t

2750

Solution steps

\int_{1}^{3} 95 + 300 t^{2} - 10 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 95 d t + \int_{1}^{3} 300 t^{2} d t - \int_{1}^{3} 10 t d t

\int_{1}^{3} 95 d t = 190

\int_{1}^{3} 300 t^{2} d t = 2600

\int_{1}^{3} 10 t d t = 40

= 190 + 2600 - 40

Simplify

= 2750

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What is the integral from 1 to 3 of 95+300t^2-10t ?
The integral from 1 to 3 of 95+300t^2-10t is 2750