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Popular >

integral from 0 to 4 of (x^2+x)

Solution

\int_{0}^{4} (x^{2} + x) d x

Solution

\frac{88}{3}

+1

Decimal

29.33333 \dots

Solution steps

\int_{0}^{4} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x + \int_{0}^{4} x d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} x d x = 8

= \frac{64}{3} + 8

Simplify

\frac{64}{3} + 8 : \frac{88}{3}

= \frac{88}{3}

Graph

Popular Examples

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\int_{1}^{3} (\frac{3}{4} x^{2} - 2) d x

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\int_{3}^{8.2} x^{2} - 10 x + 50 d x

integral from 0 to pi of sin(6x)

\int_{0}^{π} sin (6 x) d x

integral from 0 to 1 of x^4(1-x)^3

\int_{0}^{1} x^{4} (1 - x)^{3} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (x^2+x) ?
The integral from 0 to 4 of (x^2+x) is 88/3