What is the integral from 2 to 10 of sqrt(y-1) ?

The integral from 2 to 10 of sqrt(y-1) is 52/3

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integral from 2 to 10 of sqrt(y-1)

\int_{2}^{10} y - 1 d y

\frac{52}{3}

Decimal

17.33333 \dots

Solution steps

\int_{2}^{10} y - 1 d y

Apply u-substitution

: \int_{1}^{9} u d u

= \int_{1}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{9}

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

\frac{52}{3}

= \frac{52}{3}

\int_{2}^{4} f (x + 6) d x

\int_{0}^{2} (x^{3} + 2) d x

\int_{- 4}^{4} 5 + 16 - x^{2} d x

\int_{- \infty}^{1} \frac{1}{x ^{4}} d x

\int_{0}^{5} - 2 x^{2} + 10 x d x

What is the integral from 2 to 10 of sqrt(y-1) ?
The integral from 2 to 10 of sqrt(y-1) is 52/3