What is the integral from 4 to 9 of 1/(sqrt(x))-2 ?

The integral from 4 to 9 of 1/(sqrt(x))-2 is -8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 4 to 9 of 1/(sqrt(x))-2

\int_{4}^{9} \frac{1}{x} - 2 d x

- 8

Solution steps

\int_{4}^{9} \frac{1}{x} - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{9} \frac{1}{x} d x - \int_{4}^{9} 2 d x

\int_{4}^{9} \frac{1}{x} d x = 2

\int_{4}^{9} 2 d x = 10

= 2 - 10

Simplify

= - 8

\int_{0}^{1} x^{4} (1 - x)^{4} d x

\int_{0}^{60} 10 (1 + \frac{x}{60})^{2} d x

\int_{0}^{2 π} cos^{2} (2 θ) d θ

\int_{- 8}^{4} \frac{x}{2} - 8 - x d x

\int_{1}^{2} 10 - 5 x d x

What is the integral from 4 to 9 of 1/(sqrt(x))-2 ?
The integral from 4 to 9 of 1/(sqrt(x))-2 is -8