What is the integral from 0 to pi of 36sin(x) ?

The integral from 0 to pi of 36sin(x) is 72

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi of 36sin(x)

\int_{0}^{π} 36 sin (x) d x

72

Solution steps

\int_{0}^{π} 36 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 36 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 36 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 36 \cdot 2

Simplify

= 72

\int_{- \frac{1}{2}}^{\frac{1}{2}} 0.75 (1 - x^{2}) d x

\int_{- 8}^{4} - x^{2} - 3 x d x

\int_{1}^{9} \frac{x - x}{x} d x

\int_{2}^{5} (2 + 2 x + 3 x^{2}) d x

\int_{- 1}^{2} (1 + 2 x - x^{2}) - (x - 1) d x

What is the integral from 0 to pi of 36sin(x) ?
The integral from 0 to pi of 36sin(x) is 72