What is the integral from 0 to 1 of ycos(y^2) ?

The integral from 0 to 1 of ycos(y^2) is 1/2 sin(1)

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integral from 0 to 1 of ycos(y^2)

\int_{0}^{1} y cos (y^{2}) d y

\frac{1}{2} sin (1)

Decimal

0.42073 \dots

Solution steps

\int_{0}^{1} y cos (y^{2}) d y

Apply u-substitution

: \int_{0}^{1} \frac{cos ( u )}{2} d u

= \int_{0}^{1} \frac{cos ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{1} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{2} [sin (u)]_{0}^{1}

Compute the boundaries:

sin (1)

= \frac{1}{2} sin (1)

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\int_{8}^{12} (8 - x) (x - 12) d x

What is the integral from 0 to 1 of ycos(y^2) ?
The integral from 0 to 1 of ycos(y^2) is 1/2 sin(1)