What is the integral from 1 to 3 of (x-2)^3 ?

The integral from 1 to 3 of (x-2)^3 is 0

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integral from 1 to 3 of (x-2)^3

\int_{1}^{3} (x - 2)^{3} d x

0

Solution steps

\int_{1}^{3} (x - 2)^{3} d x

Apply u-substitution

: \int_{- 1}^{1} u^{3} d u

= \int_{- 1}^{1} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{- 1}^{1}

= [\frac{u ^{4}}{4}]_{- 1}^{1}

Compute the boundaries:

0

= 0

\int_{0}^{\infty} e^{- y x} d x

\int_{0}^{2} x (2) d x

\int_{2}^{4} (2 x + 4)^{4} d x

\int_{- 3}^{- 1} x - 4 d x

\int_{- 1}^{1} (1 - x^{2}) d x

What is the integral from 1 to 3 of (x-2)^3 ?
The integral from 1 to 3 of (x-2)^3 is 0